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2x^2-150x-25000=0
a = 2; b = -150; c = -25000;
Δ = b2-4ac
Δ = -1502-4·2·(-25000)
Δ = 222500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{222500}=\sqrt{2500*89}=\sqrt{2500}*\sqrt{89}=50\sqrt{89}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-50\sqrt{89}}{2*2}=\frac{150-50\sqrt{89}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+50\sqrt{89}}{2*2}=\frac{150+50\sqrt{89}}{4} $
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